Moore's law says that the number of transistors in a dense integrated circuit increases by 41% every year.
In 1974, a dense integrated circuit was produced with 5000 transistors.
Which expression gives the number of transistors in a dense integrated circuit in 1979?

The expression is    

The number of transistors in a dense integrated circuit in 1979 is

Step-by-step explanation:

we know that

The equation of a exponential growth function is equal to

where

y ----> is he number of transistors in a dense integrated circuit

x ----> is the number of years since year 1974

a ---> is the initial value or y-intercept

r ---> is the rate of change

In this problem we have

substitute

Find the number of transistors in a dense integrated circuit in 1979

we have that

x=1979-1974=5 years

substitute the value of x in the exponential equation

-----> the expression

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x