What are possible rational roots of polynomial function 0= 3x^8 + 11x^5+4x+6

1,-1,2,-2,3,-3,6,-6, 1/3, -1/3, 2/3, -2/3

Step-by-step explanation:

Factors of the constant which are:

+1,-1,+2,-2,+3,-3,+6,-6

Also, these divided by the factors of the leading coefficient (3 in this case)

Factors of 3 are 1 & 3

Dividing by 1 will give the same values

Dividing by 3:

1/3,-1/3,2/3,-2/3,3/3,-3/3,6/3,-6/3

1/3,-1/3,2/3,-2/3,1,-1,2,-2

Distinct possibilities:

1,-1,2,-2,3,-3,6,-6, 1/3, -1/3, 2/3, -2/3

answer: 298143

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.