Two planes leave an airport at the same time and travel opposite directions. One plane travels 98 km/h faster than the other one. If the two planes are 3668 Km apart after 2 hours, what is the rate of each plane. Any help with this would be grateful . In desperate need of help here .any takers ?

Step-by-step explanation:

               Let x = the speed of plane A

  Then 98 + x  = the speed of Plane B

   and 98 + 2x = the speed at which the planes are separating

and 2(98 + 2x) = their separation after 2 h

Check:

OK

the answer will be

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.