A, C and D are points on a circle, centre 0.
AB and CB are tangents to the circle.
Angle ABC = 74°
Work out the size of angle ADC.
Show your working clearly.

∠ ADC = 53°

Step-by-step explanation:

Note the angle between the radius and the tangent is 90°

The sum of the angles in quadrilateral AOCB = 360°, thus

∠ AOC = 360° - (90 + 90 + 74 )° = 360° - 254° = 106°

∠ AOC is twice the angle on the circumference ∠ ADC, thus

∠ ADC = 106° ÷ 2 = 53°

i dont know sorry

step-by-step explanation:

after going and makeing graphs i would go with a,

there is nothing that is matches the graph. if there was i would show you. but therefore my answer is a.

hope i

-lavira: )