Find an equation of the line passing through the point (5,4) and perpendicular to the line 2x+y=3

Step-by-step explanation:

Given equation of line is:

Equating it with we find:

Let the slope of required line be

Required line is parallel to the given line.

Required line passes through (5, 4) and has a slope

Equation of line in slope point form is given as:

Hence, x -2y + 3=0 is the required equation of line.

  x -2y = -3

Step-by-step explanation:

The line perpendicular to

  ax +by = c

through point (h, k) can be written as ...

  b(x -h) -a(y -k) = 0 . . . . . swap x and y coefficients, negate one of them.

Putting this in standard form gives ...

  bx -ay = bh -ak

For a=2, b=1, and (h, k) = (5, 4), this is ...

  x -2y = 5 -2(4) = -3

  x -2y = -3

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The graph shows the two lines and the point.

step-by-step explanation:

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21/58.

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