A basketball diamond is actually a square with sides of 90 feet. If a runner tries to steal second base, how far must the catcher, at home plate, throw to get the runner "out"?

127.28 feet

Step-by-step explanation:

Given

Shape of basketball diamond = Square

Length of a side = 90 feet

If the length of a side is 90 feet then the length of other sides is 90 feet.

By finding how far the catcher, at home plate, throw to get the runner "out", we are basically finding the distance from 2nd base to home

This means we're calculating the diagonal of the field..

(Since the field is a square, it has a right angle at 1st base)

Let the diagonal be representing by x.

From Pythagoras,

x² = 90² + 90²

x² = 8100 + 8100

x² = 16200

x = √16200

x = 127.2792206135785

x = 127.28 feet Approximated

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

the answer is 40.

proof: