Find the equation for the line passing through the points (3,-9) and (4,-10)

y = - x - 6

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m = change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (3,-9) and (4,- 10)

y2 = - 10

y1 = - 9

x2 = 4

x1 = 3

Slope,m = (- 10 - - 9)/(4 - 3) = - 1/1 = - 1

To determine the intercept, we would substitute x = 4, y = - 10 and m = - 1 into y = mx + c. It becomes

- 10 = - 1 × 4 + c

- 10 = - 4 + c

c = - 10 + 4

c = - 6

The equation becomes

y = -x - 6

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answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°