Introduction to variability A researcher is studying psychological factors in artistic achievement among teenage girls. One variable she is particularly interested in is determination. What information does a measure of variability for the variable determination convey? Check all that apply.
Do all teenage girls have the same amount of determination?
How consistent are the values for determination among teenage girls?
What is the central tendency for the variable determination among teenage girls?
How spread out are the values for determination amoung teenage girls?

a. Do all teenage girls have the same amount of determination

d. How spread out are the values for determination among teenage girls

Step-by-step explanation:

A central tendency is defined as the value that describes a set of data by showing the central value within the data set. The mode shows the value that occurs most often and therefore is not a measure of variation.

Two statements which are not consistent with a measure of variability are: "what is the central tendency for the variable determination among the teenage girls," and "how consistent are the values for determination among teenage girls" because the mode is the central tendency which indicates the most common value of a variable and as we mentioned earlier, is not a measure of variation.

The correct statements are therefore: "Do all teenage girls have the same amount of determination," and "How spread out are the values for determination among teenage girls", as measures of variation show how the variable values are dispersed from their mean.

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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