Ten is the average number of oil tankers arriving each day at a certain port city. The facilities can handle at most 15 tankers per day. What is the probability that on a given day, tankers will have to be turned away?

The probability of more than 15 tankers arrival is = P = 0.0487 = 4.8 %

Step-by-step explanation:

The poisson probability will be used to solve this question.

Let the probability of arriving k tankers = P (k) = e^-λ x (λ ^k / k!)

Where λ = average number of tankers arriving today.

Now calculating this equation through a spread sheet and taking sum of all 15 values,

P(k) = 0.9513

therefore

P (>15) = 1 - P(k)

P (>15) = 1 - 0.9513

P (>15) = 0.0487

P (>15) = 48 %

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.