Which function has only one x-intercept at (−6, 0)?

f(x) = x(x − 6)
f(x) = (x − 6)(x − 6)
f(x) = (x + 6)(x − 6)
f(x) = (x + 6)(x + 6)

Step-by-step explanation:

Let's find the roots of every function:

Expand the left side:

Using quadratic formula:

Therefore:

Hence, the first function has two roots:

Analizing the second function:

It's easy to see that it has a repeated root at x=6

Now, the third function:

Also, it's simple to conclude that it has two roots at x=6 and x=-6

Finally the fourth function:

has a repeated root at x=-6, which satisfies the problem condition

Aditionally I attached the graph of every function, so you will be able to check the result easily.

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)