Find the area, to one decimal place, of a 5 cm square with a 1 cm hole cut at the center

Area of the square with the hole is 4.2 square units

Step-by-step explanation:

Given:

Side of the square =  5 cm

Diameter of the hole  =  1 cm

To Find:

Area of the square with the hole = ?

solution

Step 1: Finding the area of the square

Area of the square  =

Area of the square  =

Area of the square  =  25 square units

Step 2: Finding the area of the hole

Area of the hole =

Area of the hole =            

Area of the hole = 0.785 square units

Step 3: Finding the Area of the square with the hole

Area of the square with the hole =   area of the square  -  area of the hole

Area of the square with the hole =   25  -  0.785

Area of the square with the hole =   4.215 square units

Area of the square with the hole =   4.2 square units (rounding off to one decimal)

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.