Based on an online poll, 35% of motorists routinely use their cell phone while driving. Tree people are chosen at random from a group of 100. A) What is the probability of at least two people of the three people use their cell phone while driving? B) What is the probability that no more than one person of the three people use their cell phone while driving?

The anwerss to the question are

(A) P(No less than two people use their phones while driving) =  0.1225

(B) P(The probability that no more than one person of the three people use their cell phone while driving) = 0.147875

Step-by-step explanation:

The given relations are

Percentage of motorists that routinely drive while sing their phone = 35 %

The probaboloty that if a peerson is random;ty  selected from a group of hudred person routinely uses their phone wjile friving P(phone) = 35

The probability that a  motorist randomly selected fron a set of 100 do not routinely use thir phones while driving = P(No celll phone)  = 65

Then the probability that when three people are selected at random at least two people of the three people use their cell phone while driving is

P(phone)  = 35/100m = 0.35

P(No celll phone)  = 65/100 = 0.65

(A) Probability of at least two of three use their phones whle driving is

0.35×0.35×0.65 +0.35×0.35×0.35 = 0.1225

(B) The probability of only one person out of three seted use their phones while driving is

(0.35)(0.65)(0.65) = 0.147875

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

i think the answer is b