For what value of c is the relation a function?

StartSet (2, 8), (12, 3), (c, 4), (negative 1, 8), (0, 3) EndSet

{ c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

Step-by-step explanation:

Considering the set

As we know that

So, the value of c must not be equal to 2, 12, -1, 0 i.e. c ≠ 2, 12, -1, 0

Therefore,

                   { c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

-1/3(x+1)^5

i’m pretty sure this is correct

the answer for the question that you are asking is 4