Generate n = 100 observations from the autoregression x_t=-0.9x_t-2)+x_t, Where {x_t } is white noise with σ^2 = 1. Next, apply the moving average v_t=(x_t+x_(t-1)+x_(t-2)+x_(t-3))/4 to x_t, the data you generated. Comment on the behavior of {x_t}, and how moving average changes this behavior. Hint: v = filter(x, rep(1/4, 4), sides=1) Repeat (a) but with x_t=cos⁡〖(2πt/4)〗 Repeat (b) but with x_t=cos⁡〖(2πt/4)〗+w_t Compare (a) to (c).

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

i don't see any

step-by-step explanation:

y=sec x is the correct answer

~batmans wife dun dun