Find the equation of the line that passes through the following lines points (0,-1) and (3,12).

y=13/3x-1

Step-by-step explanation:

k=(y2-y1) /(x2-x1)

A(0,-1) x1=0,y1=-1

B(3,12) x2=3, y2=12

k=(12-(-1))/(3-0)

k=(12+1)/3

k=13/3

y-y1=k(x-x1)

y-(-1)=13/3(x-0)

y+1=13/3*x

y=13/3*x-1