A cat chases a mouse. The cat is originally 4 feet behind the mouse, which is running in the same direction along the same route as the cat. If the cat's speed is 17 feet per second and the mouse's speed is 12 feet per second, how long will it take the cat to catch up with the mouse?

4/5 seconds

Step-by-step explanation:

The time = 4 / {17-12} = 4/5 seconds

Sidenote: Hope this helps!

there is no diagram : /

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.