Find the 10th term of a geometric sequence with the first element of 5 and a common ratio of 2

Step-by-step explanation:

Sol^n, Here

First term(a)= 5

Common ratio(r)= 2

We know that

tn= ar^n-1

10= 5×2^10-1

= 5×2^9

= 5×512

= 2560

Hence, the 10th term is 2560

Answer

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

because i took test