Delivery service a charges 10 for a pickup and 0.10 per mile delivery service b charges 0.25 per mile at how many miles is the cost of the two services the same

Given that,

Delivery service A charges 10 for a pickup and 0.10 per mile

Let "x" be the number of miles

Therefore,

Cost = 10 + 0.10(number of miles)

Cost = 10 + 0.10x ----- eqn 1

Delivery service b charges 0.25 per mile

Therefore,

Cost = 0.25(number of miles)

Cost = 0.25x ------ eqn 2

At how many miles is the cost of the two services the same

Eqn 1 = eqn 2

10 + 0.10x = 0.25x

0.25x - 0.10x = 10

0.15x = 10

Divide both sides by 0.15

Thus at 67 miles, cost of the two services is the same