The solution set of the quadratic inequality is {x|x= 2}
Computation:
The equation will use the cross-division method along with the quadratic expression of:
![(a+b)^2=a^2-2ab+b^2](/tpl/images/0518/8265/53aa4.png)
In the given expression:
a is x
b is 2
Solving the quadratic equation:
![4(x + 2)^2 \leq 0\\(x+2)^2\leq \frac{0}{4}\\(x+2)^2=0](/tpl/images/0518/8265/1fddf.png)
Now, simplifying the expression:
![(x+2)^2\\x^2-4x+4](/tpl/images/0518/8265/f25df.png)
Applying the quadratic formula we get;
![x \leq 2](/tpl/images/0518/8265/7bdfe.png)
As, the quadratic equation is having only one solution for the expression, therefore the value of x will be equal to 2 only.
Thus, the correct, solution for the set expression is {x|x= 2}
To know more about quadratic equations, refer to the link:
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