A 6.50 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the end of the rope, and the height of the crate above its initial position is given by y(t)=(2.80m/s)t+(0.610m/s3)t3. What is the magnitude of F when t = 4.00 s?

Step-by-step explanation:

We are given that

Mass of crate=m=6.5 Kg

Height,

We have to find the magnitude of F when t=4 s

Differentiate w.r.t t

Again differentiate w.r.t t

Substitue t=4

Where

Substitute the values

4096 bacteria

step-by-step explanation:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3