Distance, Speed, and Time A pilot flew a jet from Montreal to Los Angeles, a distance of 2500 mi. On the return trip, the average speed was 20% faster than the outbound speed. The round-trip took 9 h 10 min. What was the speed from Mon- treal to Los Angeles?

= 54.5 mi/hour

Step-by-step explanation:

The speed= distance / time

let convert time to hour

9h 10m =9h + 10/60h = 9.17 hours

speed= 2500/9.17

speed=  272.7 mi/hour

The 20% faster than the outbound speed will be:

20/100 ×272.7

=54.5 mi/hour

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

13cm

step-by-step explanation:

(apex)