If n is prime number then 2n-1 is prime also?

Step-by-step explanation:

Prime numbers are number that can only be divided by itself and 1.

E.g 2,3,5,7,11,13,17,19,23,29 etc.

So, note that this sequence doesn't have a pattern, it is neither Geometry Progression nor Arithmetic Progression.

Now, let take look at the model given

If n is prime, then 2n-1 is prime

Let take 5 for

n=5 is a prime number

2n-1=2(5)-1=10-1=9

9 is not a prime number so the model doesn't work

A prime number doesn't have sequence so, it cannot be model with sequence.

I hope this help

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: