In the cube shown below, the distance between vertices 2 and 6 is 17 cm.

If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?

256 sq cm

Step-by-step explanation:

cube is a three-dimensional figure with six congruent square faces. Since each face is congruent, each of the edges have the same length.

The cross-section described is shown below.

The cross-section is also a square which is congruent to the other faces of the cubes. Therefore, the edges of the cross-section will each measure 16 cm. Find the area by using the formula for the area.

           A=lw

               =(16cm) (16cm)

                  =256 sq cm  

So, the area of the cross-section is 256 sq cm.

answer: do you still need this?

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )