Find a degree 3 polynomial that has zeros - 1, 3 and 8 and in which the coefficient of x^2 is -40

Answer is 4x^3-40x^2+52x+96

Step-by-step explanation:

(x+1)(x-3)(x-8)=

(x^2-3x+x-3)(x-8)=

(x^2 -2x-3)(x-8)=

x^3-8x^2-2x^2+16x-3x+24=

x^3-10x^2+13x+24

because coeficient of x^2 is - 40, we multiply the whole equation by 4, then

4x^3-40x^2+52x+96.

i would say c is the best answer, hope it's right!

good luck! =)

cutie~

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b