If a seed is planted, it has a 85% chance of growing into a healthy plant.

If 7 seeds are planted, what is the probability that exactly 3 don't grow?

answer:

idk

Step-by-step explanation:

answer:

Binomial Probability

(N choose k) p^k (1-p)^(n-k)

N=7  seeds planted

p= 100% - 70% = 30% = 0.3 <--- we are interested in the plant NOT growing

(1-p) = 70% = 0.7  <--- 70% chance the plant will survive and grow

k=4  <--- we want four of them to fail

The probability is:

 (7 choose 4) * (0.3)^4  (0.7)^3 =  

 7!/(4!3!) (0.3)^4 (0.7)^3  =

 (7*6*5/3*2) (0.3)^4 (0.7)^3 =  

 7*5 (0.3)^4 (0.7)^3 =

 35 * 0.0081 * 0.343 = 0.0972405 = 9.72405%

Step-by-step explanation:

the answer is 28

step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1