A model rocket is launched straight upward. The path of the rocket is modeled by h = -16t2 + 200t, where h represents the height of the rocket and t represents the time in seconds. a. What is its maximum height? b. Is it still in the air after 8 seconds? Explain why or why not. c. Is it still in the air after 14 seconds? Explain why or why not.

a) 625

b) Yes

c) No

Step-by-step explanation:

a)To calculate the maximum height we can use the derivative to find the slope of the function.

To find the slope we make the equation equal to 0:

The slope at 0 is t=200/32=6.25[/tex]

The maximum height at t=6.25 is

The maximum height is 625

b) at t=8

The height will be 576 which is less than 625

The two x-intercepts are when h=0:

c)

The ball is not in the air because the ball will only be in the air from t=0 to t=12.5

answer:

c. the third graph

x-3y=4

step-by-step e