A parking lot has two entrances. Cars arrive at entrance I according to a Poisson distribution at an average of 3 per hour and at entrance II according to a Poisson distribution at an average of 2 per hour. What is the probability that a total of 3 cars will arrive at the parking lot in a given hour? What is the probability that less than 3 cars will arrive at the parking lot in a given hour?

P(X=3cars) = 0.052

P(X>3 cars) = 0.00638

Step-by-step explanation:

In total there are 7 cars per hour.

Using formulae for geometric Probability

P(X=3) = (7^3×e-7)/3! = 0.0521

P(X>3cars) = (7^2× e-7)/2! =

P(X>3) = 0.0128/2×1 =0.00638

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.