A fly that is heterozygous for both traits (GgEe) is crossed with one that has vestigial wings and sepia eyes (see). How many out of 16 are normal wings, red eyes

The question is incomplete soI am writing the complete question below:

These letters represent the genotypes and phenotypes of the fruit flies.

GG = Normal Wings           EE = Red Eyes

Gg = Normal Wings           Ee = Red Eyes

gg = vestigial wings           ee = sepia eyes

A fly that is heterozygous for both traits (GgEe) is crossed with one that has vestigial  wings and sepia eyes (ggee).

How many out of 16 are normal wings, red eyes?

Out of 16 there are 4 flies which have normal wings and red eyes.

Step-by-step explanation:

A fly (GgEe) is crossed with (ggee). So we will use a Punnett square to calculate the alleles of their offspring.

For wings i.e. Gg x gg:

         G         g

g       Gg      gg

g       Gg      gg

There are 2 flies with Gg (Normal Wings) and two flies with gg (Vestigial wings. The probability of both is 2/4.

For eyes i.e. Ee x ee

         E        e

e       Ee       ee

e       Ee       ee

There are 2 flies with red eyes (Ee) and 2 flies with sepia eyes (ee). the probability of both is 2/4.

No. of flies with normal wings (Gg) and red eyes (Ee) = 2/4 x 2/4

No. of flies with normal wings (Gg) and red eyes (Ee) = 4/16

So, out of 16 there are 4 flies which have normal wings and red eyes.

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation:

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