The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 51 and a standard deviation of 10. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 51 and 61? Do not enter the percent symbol. ans = 95 Incorrect %

The probability that the light bulb replacement requests numbering is between 51 and 61 is 0.34.

Step-by-step explanation:

Let X = number of daily requests to replace florescent light bulbs.

It is provided that

The 68-95-99.7 rule states that:

Compute the probability that the light bulb replacement requests numbering is between 51 and 61 as follows:

**Consider the diagram below.

Thus, the probability that the light bulb replacement requests numbering is between 51 and 61 is 0.34.

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake