A right triangle has the side legnths 4 units, 5 units, and x units. It is unknown if the missing length is the longest or shortest side.
Rounded to the nearest tenth, what is the difference between the possible values of x ?

For longest x = 6.4

For shortest x = 3

Step-by-step explanation:

Given a right angle triangle with lengths 4 units and 5 units and x units .

x can be gotten using Pythagoras theorem .

If x Is the longest side , then

x^2 = 5^2 + 4^2

= 5x5 + 4x4

= 25 + 16

x^2 = 41

x = squared root of 41

x = 6.4

If x is the shortest side ,

x^2 = 5^2 - 4^2

= 5x5 - 4x4

= 25 - 16

x^2 = 9

x = squared root of 9

x = 3

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5