The coordinates of the vertices of quadrilateral ABCD are (7, -7), (4, -10), (1.5, -2.5), and (6, -3), respectively. If quadrilateral ABCD is rotated 180° counterclockwise about the origin, what are the coordinates of D'? A. (6, 3) B. (3, -6) C. (-6, 3) D. (-3, 6)

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

don't know sorry bru

step-by-step explanation:

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)

answer: 1+1

step-by-step explanation: 1+1 is at least 2