Match the mean median mode and range for the data set below 16 9 20 10 12 6 8 15

12 is mean     11 is median     range is 14

Step-by-step explanation:

For the Mean

Add all the numbers up

16 + 9 + 20 + 10 =55

12 + 6 + 8 + 15 = 41

55 + 41 = 96

There are 8 numbers so we divide by 8

96/8 = 12

Range is Smallest number minus biggest so 20 - 6 = 14

Mean: 12

Median: 11

Mode: No Mode

Range: 14

Step-by-step explanation:

Mean:

- To calculate the mean, add up all the numbers, and divide by the number of numbers there are.

16 + 9 + 20 + 10 + 12 + 6 + 8 + 15 = 96

96 divide by 8 = 12

Median:

- Order the numbers from least to greatest, and find the middle number!

6, 8, 9, 10, 12, 15, 16, 20

Since there is NO middle number, because there are 8 numbers, add the two numbers (10 + 12), and divide by 2.

10 + 12 = 22

22 divided by 2 = 11

Mode:

The mode is the number that appears most often. Since NO number appears more than once, there is no mode.

Range:

- The range is the difference between the highest number and the lowest.

Highest Number: 20

Lowest Number: 6

20 - 6 = 14

Hope this helps!

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt