Yulet rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 7.

the answer is 1/6

Step-by-step explanation:

Let (a,b) denote a possible outcome of rolling the two die, with a the number on the top of the first die and b the number on the top of the second die. Note that each of a and b can be any of the integers from 1 through 6. Here is a listing of all the joint possibilities for (a,b):  

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

With the above declaration, the outcomes where the sum of the two dice is equal to 7 form an event. If we call this event E, we have

E={(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}.

so Possibilities(P) of having Event (E)

P(E)=6/36

= 1/6

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step-by-step explanation:

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graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: