H(x) = x^2 - 1
Over which interval does h have a negative average rate of change?

The Curve has negative rate of change for negative values of x

I.e in the interval - infinity to 0

Step-by-step explanation:

Step 1:

The change in the rate for the given function is obtained calculating the first derivative.

So dy/dx = dH(x)/dx = 2*x

Step 2:

This rate of change will be negative when the dy/ dx is less than 0

So dy/dx = 2x < 0 => x< 0

So for values of x less than 0 the function has negative values for the rate of change.

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation: