Mrs. Fox, the art teacher at Eastside Elementary school, has an empty space on her wall 6 ft.* 3 1/3 ft. She was given some white tiles that measure 1/3 ft. by 1/3 ft. She wants her 175 fifth grade students to each design and paint a tile to be hung in the empty space on the wall. Will there be enough room in the designed space to hang all 175 tiles?
What is the area of the space Mrs. Fox wants to fill? Justify your answer with words, diagrams, or an equation for both questions.

1. The space Mrs. Fox wants to fill is bigger than the space needed to hang 175 tiles , therefore it will be enough room in the designed space.

2. The area of the space Mrs. Fox wants to fill is 20 ft².

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Empty space Mrs. Fox has on her wall = 6 ft. * 3 1/3 ft.

White tiles measures Mrs. Fox was given = 1/3 ft. * 1/3 ft.

2. She wants her 175 fifth grade students to each design and paint a tile to be hung in the empty space on the wall. Will there be enough room in the designed space to hang all 175 tiles?  What is the area of the space Mrs. Fox wants to fill? Justify your answer with words, diagrams, or an equation for both questions.

Let's recall the formula for the area of a rectangle:

Area = Length * Width

Area = 6 ft * 3 1/3 ft.

Area = 6 * 3.33 = 20 ft²

The area of the space Mrs. Fox wants to fill is 20 ft²

Now, let's find the area of each white tile and let's multiply that value 175 times, as follows:

Area of a white tile = 1/3 * 1/3

Area of a white tile = 0.33 * 0.33 = 0.1089 ft²

Area of 175 tiles = 0.1089 * 175 = 19.06 ft² (rounding to two decimal places)

20 ft² > 19.06 ft² or the space Mrs. Fox wants to fill is bigger than the space needed to hang 175 tiles , therefore it will be enough room in the designed space.

answer: 2530

hope this

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204