The amount of carbon-14 ( _6^14text(C)) in a wooden artifact is measured to be 12.5 percent the amount in a fresh sample of wood from the same region. The half-life of carbon-14 is 5715 years. Assuming the same amount of carbon-14 was initially present in the artifact, determine the age of the artifact.

17145 years

Step-by-step explanation:

Let n be the quantity of carbon-14 in the wooden artifact and n₀ be the quantity in the fresh sample of wood. The percentage of carbon -14 in the wooden artifact = 12.5%. This implies that n/n₀ = 12.5/100 = 0.125

For the carbon-14 to decay to 12.5% of its original value, it takes

(1/2)ⁿ have lives  which equals 0.125

(1/2)ⁿ = 0.125 = 125/1000 = 1/8 = 1/2³

So, n = 3. It becomes 12.5% after three half lives.

So the original age of the artifact = 3 × half - life = 3 × 5715 = 17145 years

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

351°f

step-by-step explanation: