Wear-out of used display panels. Wear-out failure time of electronic components is often assumed to have a normaldistribution. Can the normal distribution be applied to the wear-out of used manufactured products, such as coloreddisplay panels? A lot of 50 used display panels was purchased by an outlet store. Each panel displays 12 to 18 colorcharacters. Prior to acquisition, the panels had been used for about one«third of their expected lifetimes. The data in theaccompanying table (saved in the file) give the failure times (in years) of the 50 used panels. Use the techniques of thissection to determine whether the used panel wear-out times are approximately normally distributed.0.01 1,21 1.71 230 296 0,19 1.22 1.75 230 298 0.511.24 1.77 241 3.19 0.57 1.48 1.79 244 3.25 0.70 1,541.88 257 3,31 0.73 1.59 1.90 261 1.19 0.75 1.61 1.9362 3.50 0.75 1,61 201 272 3.50 1.11 1.62 216 2763.50 1.16 1.62 218 284 3.50Source: Based on Irony, T, Z., Lauretto, M,, Pereira, C., & Stern, J. M. "A Weibull wearout test: Full Bayesian approach," paperpresented at Mathematical Sciences Colloquium, Binghamton University, Bringhamton, UK, December 2001,

step-by-step explanation:

this woman was an important writer and propagandist during the american revolution. she was a member of the committee of correspondence (in fact the committee was formed in her home) and was an advisor to many of the revolutionary leaders, including george washington and john adams. who was this revolutionary woman?

4th option is correct xy=-10

if this was to u plzz mark me the brainliest

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3