Which of the following equations can be a harmonic on a string that is 10 cm long? Select all that apply. (three correct answers)
A.) y=2sin(pi/5 x)
B.) y=2sin(2pi/7 x)
C.) y=2sin(pi/10 x)
D.) y=2sin(10pi x)
E.) y=2sin (5/2pi x)

The options are: A, C and D

Step-by-step explanation:

The sine wave has a general form : y = A sin (BX)

Where A is the amplitude and B = 2π/period

So, we will check which of the options will be a harmonic on a string that is 10 cm long.

A.) y=2sin(pi/5 x)

B = π/5 ⇒ period = 2π/B = 2π ÷ π/5 =  2π * 5/π = 10

So, one cycle of y=2sin(pi/5 x) will be a harmonic on a string that is 10 cm long.

B.) y=2sin(2pi/7 x)

B = 2π/7 ⇒ period = 2π/B = 2π ÷ 2π/7 =  7  

C.) y=2sin(pi/10 x)

B = π/10 ⇒ period = 2π/B = 2π ÷ π/10 = 20 = 2 * 10

So, half a cycle of y=2sin(pi/10 x) will be a harmonic on a string that is 10 cm long.

D.) y=2sin(10pi x)

B = 10π ⇒ period = 2π/B = 2π ÷ 10π = 1/5 = 10/50

So, 50 cycles of y=2sin(10pi x) will be a harmonic on a string that is 10 cm long.

E.) y=2sin (5/2pi x)

B = 5/2π ⇒ period = 2π/B = 2π ÷ (5/2π) = 4π²/5

So, options A, C and D can be a harmonic on a string that is 10 cm long.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

it would be 6xy and -16xy.