A high-profile consulting company chooses its new entry-level employees from a pool of recent college graduates using a five-step interview process. Unfortunately, there are usually more candidates who complete the interview process than the number of new positions that are available. As a result, cumulative GPA is used as a tie-breaker. GPAs for the successful interviewees are Normally distributed with a mean of 3.3 and a standard deviation of 0.4. Out of 163 people who made it through the interview process, only 121 can be hired. What cut-off GPA should the company use?

a. 3.00
b. 3.04
c. 3.08
d. 3.12

Option B) 3.04

Step-by-step explanation:

We are given the following in the question:

Number of people interviewed,n = 163

Number of people hire, x = 121

Proportion of people hire =

Mean, μ = 3.3

Standard Deviation, σ = 0.4

We are given that the distribution of GPA for the successful interviewees is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.742

Calculation the value from standard normal z table, we have,  

Thus, cut-off GPA should be 3.04.

Option B) 3.04

its kind of blurry. can you put a clearer pic?

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )