How do you do this question?

A) x ≤ -2 and 0 ≤ x ≤ 3

Step-by-step explanation:

g(x) is decreasing when g'(x) is negative.

Use second fundamental theorem of calculus to find g'(x).

g(x) = ∫₋₁ˣ (t³ − t² − 6t) / √(t² + 7) dt

g'(x) = (x³ − x² − 6x) / √(x² + 7) (1)

To find when g'(x) is negative, first find where it is 0.

0 = (x³ − x² − 6x) / √(x² + 7)

0 = x³ − x² − 6x

0 = x (x² − x − 6)

0 = x (x − 3) (x + 2)

x = -2, 0, or 3

Check the intervals before and after each zero.

x < -2, g'(x) < 0

-2 < x < 0, g'(x) > 0

0 < x < 3, g'(x) < 0

3 < x, g'(x) > 0

g(x) is decreasing on the intervals x ≤ -2 and 0 ≤ x ≤ 3.

eveidence i thing that

step-by-step explanation:

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.