The reduced row echelon form of the augmented matrix of a system of equations is given. Find the solutions of the system.
1 0 0 5 18
0 1 0 4 -5
0 0 1 0 -9
0 0 0 0 0
Enter the solution of the system below.
Use w for the parameter
x=
y=
z=
W is any real number

Step-by-step explanation:

Since w is the parameter, we assume the equations are written in the form ...

  ax + by + cz + dw = e

This means the reduced matrix is telling you ...

  x + 5w = 18

  y + 4w = -5

  z = -9

The first two of these equations can be solved for x and y by subtracting the w term:

  x = 18 -5w

  y = -5 -4w

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

-4, -2, 1, 4

step-by-step explanation:

domain = x values

range = y values