The sum of two numbers is a hundred one number is at least 16 more than the other number. What are the numbers? Please help

42 and 58

Step-by-step explanation:

Let the two numbers be represented by A And B

A + B = 100

A = B + 16

Substitute B + 16 in place of A in equation 1

We have,

B + 16 + B = 100

It can also be written as

B + B + 16 = 100

2B + 16 = 100

Subtract 16 from both sides

2B + 16 - 16 = 100 - 16

2B = 84

Divide both sides by 2

2B/2 = 84/2

B = 42

Now substitute 42 for B in any of the equations to get A.

Using equation 1

A + B = 100

A + 42 = 100

Subtract 42 from both sides

A + 42 - 42 = 100 - 42

A = 58

Therefore the two numbers are 42 and 58

answer

106 emergencies

step-by-step explanation: