Prove equal chords in the same circle subtend equal angles at circumference. Thank you!

Let AB and CD be two equal chords on the circumference. If you consider the triangles AOB and COD, where O is the center of the circumference, you have:

So, the two triangles have the same side, and are congruent by the SSS theorem.

This implies that they also have the same angles, and in particular, the angles AOB and COD are the same.

it costs $20 to interview each person for a survey. find the cost to obtain a +- 3% margin of error.

step-by-step explanation:

copy and paste, put it in google

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6