A farmer has 2400 feet of fencing and wants to fence off a rectangular field that borders a straight river. Find the dimensions of the fence to maximize the area enclosed by the fence.

w- 600ft, L-1200ft

Step-by-step explanation:

Area = width*length

A(x) = x(2400-2x)

A(x) = 2400x - 2x^2

You have a quadratic with a = -2 and b = 2400

Maximum Area occurs where x = -b/2a = -2400/(2*-2) = 600 ft. (width)

length = 2400-2x = 2400-2*600 = 1200 (length)

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!