A family plans to have 3 children. For each birth, assume that the probability of a boy is the same as the probability of a girl. What is the probability that they will have at least one boy and at least one girl?

a.0.5
b.0.125
c.0.75
d.0.875

(c), 0.75

Step-by-step explanation:

It is given that, the probability of boy is same as the probability of girl.

Number of children family plans to have = 3

Consider, B be the event that represents that child is a boy

G be the event that represents that child is a girl.

The simple events for the provided case could be written as:

S = {(GGG, BBB, GBB, BGB, BBG, BBG, GBG, GGB)}

From above simple event, it is clear that

P(3 boys) = 1/8 and P(3 Girls) = 1/8

Thus, the probability of having at least one boy and at least one girl can be calculated as:

Thus, the required probability is 0.75.

Hence, the correct option is (c), 0.75

unpaid balance is : $149.99-$50 = $99.99 new balance = 149.99+2.62-50 = $102.61 finance charge = 99.99- 0.21/12= $1.75 new balance = 99.99+1.75 = $101.74 average daily balance method average daily balance= 3399.70/30 = $113.32 finance charge = $ 0.21/12ă—113.32 = $1.98 new balance = $149.99-50+1.98 = $101.97