A teacher decided to bring a jar of 530 pieces of small candy to his 100-student classroom so students could practice estimation. The students were told that whoever had the closest guess would win the candy. Suppose we took a random sample of one third of the students and calculated the sample mean of their guesses. The distribution of individual guesses had a mean of 400 pieces of candy and a standard deviation of 3,000 pieces of candy (the students had a lot of trouble guessing the count).

Yes, because the population distribution is normally distributed, and we have a random sample.

Step-by-step explanation:

If the population is skewed, then the sample mean won't be normal for when N is small.

If the population is normal, then the distribution of sample mean looks normal even if N = 2.

If the population is skewed, then the distribution of sample mean looks more and more normal when N gets larger.

Since we have use 33% of the student, then N is large enough to conclude that the student are bad at guessing

b

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3