Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = negative 300 2nd row 5 x squared + 5 y squared = 150 EndLayout

These 2 equations has no solution and the equations are independent of each other.

Step-by-step explanation:

-10x² -10y² = -300 a

5x² + 5y² = 150 b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x