At time t equals0, a particle is located at the point (5,2,7). It travels in a straight line to the point (8,1,6), has speed 4 at (5,2,7) and constant acceleration 3 I - J- K. Find an equation for the position vector r(t) of the particle at time t.

Step-by-step explanation:

First, we integrate the acceleration fiction to obtain the velocity function.

The acceleration function, 3i - j - k, in vector form is

So,  

Where is a constant vector. To obtain , knowing that the particle has speed 4 at (5, 2, 7) at t = 0.

= 4

The particle travels in a straight line to (8, 1, 6), and (8, 1, 6) - (5, 2, 7) =

There is a constant, s, such that

So,

Therefore,

and

Next,  we find the position function by integrating the velocity function.

Where is a constant vector. To obtain , knowing that the particle is at (5, 2, 7) at t = 0.

can i get the link to the assignment?

step-by-step explanation:

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.