A rectangle has a perimeter of 14 inches. A smaller rectangle has a perimeter of 10 inches. If the length of the larger rectangle is 4 inches, what is the length of the smaller rectangle? Round to the nearest tenth.

The length of the smaller rectangle rounded to the nearest tenth is 2.9 inches

Step-by-step explanation: The question states that we have two rectangles with the perimeters given as 14 inches (larger) and 10 inches (smaller) respectively.

With this bit of information given, we can derive a ratio for both rectangles which is, ratio of larger rectangle to smaller rectangle and that equals

14:10

And this is further simplified into 7:5 ( divide both sides by 2 and reduce to their simplest form)

What this simply mean is that, for every 7 units measured on the larger rectangle, the smaller rectangle measures 5 units on the corresponding side. So if for example the larger rectangle measures 7/2 units on one side, the smaller rectangle would measure 5/2 units on the corresponding side.

Having been given the length of the larger rectangle as 4 inches, we can use the ratio we derived to calculate the length of the smaller rectangle as follows;

7:5 = 4:x OR

7/5 = 4/x

By cross multiplication we now have

7(x) = 5(4)

7x = 20

Divide both sides of the equation by 7

x = 2.86

Rounded to the nearest tenth,

x = 2.9 inches

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

addition

step-by-step explanation: