A university class has 22 students: are accounting majors, are history majors, and are nursing majors. The professor is planning to select two of the students for a demonstration. The first student will be selected at random, and then the second student will be selected at random from the remaining students. What is the probability that two accounting majors will be selected

P=number students of accounting majors/231

P=n/231 .

Step-by-step explanation:

We know that a university class has 22 students: are accounting majors, are history majors, and are nursing majors.

The professor is planning to select two of the students for a demonstration.  

We calculate the number of possible combinations for a professor of 22 students to select 2 students. We get

{22}_C_{2}=\frac{22!}{2!· (22-2)!}

{22}_C_{2}=231

We assume that  number students of accounting majors is n.

Thus, the number of favorable opportunities is n.

Therefore, the probability that two students accounting majors will be selected is

P=number students of accounting majors/231

P=n/231 .

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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